1.

ose the correct option and give justificetionnt O, the length of the tangent to a circle is 24 cm and the distance of O fromis 25 cm. The radius of the circle isthrom a point(B) 12 cm

Answer»

Let O be the centre of the circle.

Given that,

OQ = 25cm and PQ = 24 cm

As the radius is perpendicular to the tangent at the point of contact,

Therefore, OP ⊥ PQ

Applying Pythagoras theorem in ΔOPQ, we obtain

OP^2 + PQ^2 = OQ^2

OP^2 + 24^2 = 25^2

OP^2 = 625 − 576

OP^2 = 49

OP = 7 cm



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