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ose the correct option and give justificetionnt O, the length of the tangent to a circle is 24 cm and the distance of O fromis 25 cm. The radius of the circle isthrom a point(B) 12 cm |
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Answer» Let O be the centre of the circle. Given that, OQ = 25cm and PQ = 24 cm As the radius is perpendicular to the tangent at the point of contact, Therefore, OP ⊥ PQ Applying Pythagoras theorem in ΔOPQ, we obtain OP^2 + PQ^2 = OQ^2 OP^2 + 24^2 = 25^2 OP^2 = 625 − 576 OP^2 = 49 OP = 7 cm |
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