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Osmotic pressure of a solution is `0.0821 atm` at a temperature of 300 K. The concentration in mole/litre will beA. 0.033B. 0.066C. `0.33 xx 10^(-2)`D. 3 |
Answer» Correct Answer - C `C=pi/(RT) = 0.0821/(0.0821 xx 300) = 1/300 =0.33 xx 10^(-2) M ` |
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