otic pressure of 30% solution of glucose is 1.20 atmOsmatm.(1) 2.5 atmand that of 3.42% solution of canethe two solutions will beThe osmotic pressure of the mixture containing equal volumes of(2) 3.7 atm(3) 1.85 atm(4) 1.3 atm.meOD

otic pressure of 30% solution of glucose is 1.20 atmOsmatm.(1) 2.5 atm

1.	otic pressure of 30% solution of glucose is 1.20 atmOsmatm.(1) 2.5 atmand that of 3.42% solution of canethe two solutions will beThe osmotic pressure of the mixture containing equal volumes of(2) 3.7 atm(3) 1.85 atm(4) 1.3 atm.meOD
Answer» let M1 be the molarity of glucose. and M2 be the molarity for Cane -sugar . respectively. Of equal volumes would be mixed then, M1V + M2V = M(2V) M = (M1+M2)/2 would be the new concentration. From first soln. 1.20=M1ST or M1 = 1.20/ST similarly M2 = 2.5/ST Put it in M. then apply for mixed soln. O.P = 1MST ST would be canceled out. O.P=3.7/(2ST) ST=3.7/2=1.85atm