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Out of the following which pentadiens shows double bond character between `C_(2) -C(3)` bond although it appers to be a single bondA. `CH_(3)-CH=C=CH-CH_(3)`B. `CH_(2)=CH-CH=C-CH_(3)`C. `CH_(3)CH_(2)-CH=CH_(2)`D. `CH_(2)=CH-CH_(2)-CH=CH_(2)` |
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Answer» Correct Answer - B Due to delocalisation of `pi` electrons `C_(2)-C_(3)` bond acquired double bond character. |
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