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Over a solenoid of 50 cm length and 2 cm radius having 500 turns. Is wound another wire of 50 turns near the centre. Calculate mutual inductance of the two coils. If currents in primary changes From 0 to 5 a in 0.02 s, what is the emf induced in secondary coil ? |
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Answer» Here, `l = 50 cm = (1)/(2) m, r = 2 cm = 2 xx 10^(-2) m`, `N_(1) = 500 , N_(2) = 50, M = ?, dI = 5 - 0 = 5 A` `dt = 0.02 s, e= ?` `M = (mo_(0) N_(1) N_(2) A)/(l)` `= (4 pi xx 10^(-7) xx 500 xx 50 xx 3.14 (2 xx 10^(-2))^(2))/(1//2)` `= 7.896 xx 10^(-5) H` `e = (M dI)/(dt) = 7.896 xx 10^(-5) xx (5)/(0.02)` `= 19.74 xx 10^(-3) V = 19.74 mV` |
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