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Oxidation number of `Cl` in `NOClO_(4)` is:A. `+11`B. `+9`C. `+7`D. `+5` |
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Answer» Correct Answer - C The compound may be written as `NO^(+)ClO_(4)`. For `ClO_(4)^(-)`, Let oxidation number of Cl = a `a+4xx(-2)=-1` `a=+7` Hence, the oxidations number of Cl in `"NOClO"_(4)` is `+7` |
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