1.

Oxidation number of `Cl` in `NOClO_(4)` is:A. `+11`B. `+9`C. `+7`D. `+5`

Answer» Correct Answer - C
The compound may be written as `NO^(+)ClO_(4)`.
For `ClO_(4)^(-)`, Let oxidation number of Cl = a
`a+4xx(-2)=-1`
`a=+7`
Hence, the oxidations number of Cl in `"NOClO"_(4)` is `+7`


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