Oxidation number of cobalt in `[Co(NH_(3))_(6)]Cl_(2)Br` is -A. `+6`B. ZeroC. `+3`D. `+2`

Oxidation number of cobalt in `[Co(NH_(3))_(6)]Cl_(2)Br` is -A. `+6`B.

1.	Oxidation number of cobalt in `[Co(NH_(3))_(6)]Cl_(2)Br` is -A. `+6`B. ZeroC. `+3`D. `+2`
Answer» Correct Answer - C Let the oxidation number of Co be x Oxidation number of `NH_(2)` is zero Oxidation number of `Cl` is `-1` Oxidation number of Br is `-1` Hence, `x+6(0)-1xx2-1=0` `therefore" "x=+3` So, the oxidation number of corbalt in the given complex compound is `+3`.

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Oxidation number of cobalt in `[Co(NH_(3))_(6)]Cl_(2)Br` is -A. `+6`B. ZeroC. `+3`D. `+2`

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