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Oxidation number of h3p2o7- |
Answer» ANSWER:+ 5 Explanation:GIVEN : Compound H₃P₂O₇⁻ We are ASKED to find O.N. of P : We know : O.N. of H = + 1 O.N. of O = - 2 Net charge on compound is - 1 . Let O.N. of P be x . ( 1 × 3 ) + ( 2 × x ) + ( 7 × ( - 2 ) ) = - 1 3 + 2 x - 14 = - 1 2 x - 11 = - 1 2 x = + 10 x = + 10 / 2 x = + 5 Therefore , O.N. of P in H₃P₂O₇⁻ is + 5 |
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