1.

Oxidation number of h3p2o7-

Answer»

ANSWER:

+ 5

Explanation:

GIVEN :

Compound H₃P₂O₇⁻

We are ASKED to find O.N. of P :

We know :

O.N. of H = + 1

O.N. of O = - 2

Net charge on compound is - 1 .

Let O.N. of P be x .

( 1 × 3 ) + ( 2 × x ) + ( 7 × ( - 2 ) ) = - 1

3 + 2 x - 14 = - 1

2 x - 11 = - 1

2 x = + 10

x = + 10 / 2

x = + 5

Therefore , O.N. of P in H₃P₂O₇⁻ is + 5



Discussion

No Comment Found