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Oxidation number of `N` in `(NH_(4))_(2)SO_(4)` isA. `-1//3`B. `-1`C. `+1`D. `-3` |
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Answer» Correct Answer - D `(NH_(4))_(2)SO_(4) hArr 2NH_(4)^(+)+SO_(4)^(--)` `overset(**)(N)H_(4)^(+)` `x+4=+1," "x=1-4=-3`. |
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