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Oxidation number of nitrogen in `NaNO_(2)` isA. `+2`B. `+3`C. `+4`D. `-3` |
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Answer» Correct Answer - B Let the oxidation number of N in `NaNO_(2)` be x `+1+x+(-2)xx2=0` `1+x-4=0, x=+3`. |
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