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Oxidation number of nitrogen in `NaNO_(2)` isA. `+2`B. `+4`C. `+3`D. `-3` |
Answer» Correct Answer - C Let the oxidation number of `N` in `NaNO_(2)` be `x` `+1+x+(-2)xx2=0` `1+x-4=0`, `x= +3` |
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