Oxidation number of .S. in (CH_(3))_(2) SO is:

1.	Oxidation number of .S. in (CH_(3))_(2) SO is:
Answer» Solution : Alkyl GROUPS have (+1) oxidation state . `:. (CH_3)_(2)SOimplies +2+x-2=0impliesx=0` Oxidation state of SULPHUR is ZERO

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