Oxidation numbers fo iodine in ` IO_3^(-), IO_4^(-), Kl`, and `I_3` , respectively, are .A. ` +5, +7, -1, 0`B. ` -1, -5, -1, 0`C. ` -2, -5 , -1, 0`D. ` +3, +5, +7, 0`

Oxidation numbers fo iodine in ` IO_3^(-), IO_4^(-), Kl`, and `I_3` ,

1.	Oxidation numbers fo iodine in ` IO_3^(-), IO_4^(-), Kl`, and `I_3` , respectively, are .A. ` +5, +7, -1, 0`B. ` -1, -5, -1, 0`C. ` -2, -5 , -1, 0`D. ` +3, +5, +7, 0`
Answer» Correct Answer - A The algebraic sum of the oxidation number of all the atoms in a compound must be zero and in a polyatomic ion must equal the charge on the ion. Let the oxidation number or iodine be `x`. Then `IO_3^(-) rArr x+ 3(-2) =- 1` `x=+5` ` IO_4^(-) rArr x + 4 (-2) =- 1` ` x =+7` `KI rArr ( +1) + (x) =0` ` x=- 1` ` I_2 rArr 2 x =0` ` x = 0`.

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Oxidation numbers fo iodine in ` IO_3^(-), IO_4^(-), Kl`, and `I_3` , respectively, are .A. ` +5, +7, -1, 0`B. ` -1, -5, -1, 0`C. ` -2, -5 , -1, 0`D. ` +3, +5, +7, 0`

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