Oxidation of base at anode is given by the chemical equation :4OH^(-)toO_(2)+2H_(2)O+4e^(-)What is the equivalent weight of water?

Oxidation of base at anode is given by the chemical equation :4OH^(-)t

1.	Oxidation of base at anode is given by the chemical equation :4OH^(-)toO_(2)+2H_(2)O+4e^(-)What is the equivalent weight of water?
Answer» Solution :4moles of electrons =2 moles of WATER 2Faradays = 1mole of water Equivalent weight `=("molecular weight")/("number of FARADAYS")=(18)/(2)=9`