Oxidation of nitrogen monoxide was strudied at 200^@C with initial pressure of 1 atm NO and 1 atm of O_2. At equilibrium partial pressure of oxygen is found to be 0.52 atm. Calculate K_P value.

Oxidation of nitrogen monoxide was strudied at 200^@C with initial pre

1.	Oxidation of nitrogen monoxide was strudied at 200^@C with initial pressure of 1 atm NO and 1 atm of O_2. At equilibrium partial pressure of oxygen is found to be 0.52 atm. Calculate K_P value.
Answer» SOLUTION :`2NO(g) + O_2(g) hArr 2NO_2(g)` `[O_2]` at equilibrium `RARR 1 - x = 0.52` ` x = 0.48` So, `P_(NO) = 1-2x = 1 - 2(0.48) = 0.04` `P_(O_2) = 0.52` `P_(NO_2) = 2x= 2(0.48) = 0.96` `K_P ((P_(NO_2)))/((P_(NO)^2)(P_(O_2)))=(0.96 XX 0.96)/(0.04 xx 0.04 xx 0.52)` `K_P = 1.107 xx 10^3`