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Oxidation of nitrogen monoxide was studied at 200^(@)C with initial pressures of 1 atm NO and 1 atm of O_(2). At equilibrium partial pressure of oxygen is found to be 0.52 atm calculate K_(P) value. |
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Answer» <P> Solution :`2NO(G)+O_(2)(g)hArr2NO_(2)(g)` `K_(P)=((P_(NO_(2))^(2)))/((P_(NO))^(2)(P_(O)))=(0.96xx0.96)/(0.04xx.0.04xx0.52)` `K_(P)=1.017xx10^(3)` |
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