Oxidation state of each CI in CaOCI_(2) is / are

1.	Oxidation state of each CI in CaOCI_(2) is / are
Answer» 0 `+1` `-1` `+1,-1` Solution :`CaOCI_(2)` is ACTUALLY `CA^(2+)OCI^(-)CI^(-)` Therefore the O.N of the two CI ATOMS are +21 and -1

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