1.

oxidation states of P in H_(4)P_(2)O_(5),H_(4)P_(2)O_(6),H_(4)P_(2)O_(7) are respectively

Answer»

<P>`+3,+5,+4`
`+5,+3,+4`
`+5,+4,+3`
`+3,+4,+5`

Solution :O.N of P in `H_(4)P_(2)O_(5)=4(+1)+2x+5(-2)=0`
or X=+3
O.N of p in `h_(4)P_(2)O_(6)=4(+1)+2x+6(-2)=0`
or x =+4
O.N of p in `H_(4)P_(2)O_(7)=4(+1)+2x+7(-2)=0`
or x=+5


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