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Oxygen exists as three isotopes `._(8)^(16)O,_(8)^(17)O,_(18)^(18)O` with relative abundance `90%,7%` and `3%` repectively What is average atomic mass of oxygen? .

Answer» `M_(avg) = sum x_(i) M_(i) = 0.9 xx 16 + 0.07 xx 17 + 0.03 xx 18 = 16.13` amu or `16.13 g//mol` .


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