Oxygen is prepared by catalytic decomposition of potassium chlorine `(KClO_(3))`. Decomposition of potassium, chloride gives potassium chloride (KCl) and oxygen `(O_(2))`. How many moles and how many grams of `KClO_(3)` are required to produce 2.4 mole `O_(2)`?A. `196.0`B. `190.6`C. `169.0`D. `196.2`

Oxygen is prepared by catalytic decomposition of potassium chlorine `(

1.	Oxygen is prepared by catalytic decomposition of potassium chlorine `(KClO_(3))`. Decomposition of potassium, chloride gives potassium chloride (KCl) and oxygen `(O_(2))`. How many moles and how many grams of `KClO_(3)` are required to produce 2.4 mole `O_(2)`?A. `196.0`B. `190.6`C. `169.0`D. `196.2`
Answer» Correct Answer - A The balanced equation is `underset(underset(2xx(39+35.5+3xx16)=245"g")(2"mol"))(2KClO_(3)(s)+)20_(2)(g)rarr 2KCl(s) + underset(underset(2.4 "moles")(3 "mol"))(3O_(2))(g)` `because` 3 moles of `O_(2)` Is produced by decomposition of `KClO_(3) = 245`g `because 2.4` moles of `O_(2)` will be produced by the decompostion of ltb rgt `KClO_(3)=(245xx2.4)/3=196.0 "g"`

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