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Ozone an estimated in air by passing certaing volume of air through an acidified or neutral or basic KI solution when O_(2) is evolved and I^(ɵ) is oxidised to I_(2). Free I_(2) evolved is titrated with standard Na_(2)S_(2)O_(3) solution. In an experiment 10 L of air at 1 atom and 27^@C was passed through an alkaline KI solution and I_(2) liberated requried 2 " mL of " (M)/(800)Na_(2)S_(2)O_(3) solution. Calculate the volume percentage of O_(3) in sample. |
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Answer» Solution :Write the balanced REDOX REACTIONS in basic medium. `2I^(ɵ)+H_(2)O+O_(3)toO_(2)+I_(2)+2overset(ɵ)(O)H` (n factor `O_(3)=2`) `I_(2)+2e^(-)to2I^(ɵ)(n=2)` `S_(2)O_(3)+10overset(ɵ)(O)Hto2SO_(4)^(2-)+5H_(2)O+8e^(-)(n=8)` `thereforem" Eq of "I_(2)=m" Eq of "Na_(2)S_(2)O_(3)` `=2xx(1)/(800)xx8` (n factor) `=0.02` mmol es of `I_(2)=(0.02)/(2)=mmol es of O_(3)` `[becausen=2` for both or molar ratio of `O_(3):I_(2)::1:1`] `P_(O_(3))=(nRT)/(V)` `=(0.01xx10^(-3)xx0.0821xx300)/(10)` `=246.3xx10^(-7)atm` Volume `% of O_(3)=246.3xx10^(-7)xx100` `=2.463xx10^(-3)%` |
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