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P(-3, 2) is one end of focal chord PQ of the parabola `y^2+4x+4y=0`. Then the slope of the normal at Q is |
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Answer» Parabola=that tangent at one end of focal chord is parallel to normal at other end. Slope of normal at `theta`=slope of tangent at P `y^2+4x+4y=0` diff with respect to x `2ydy/dx+4+4dy/dx=0` `dy/dx=-4/(2y+4)` `=-1/2`. |
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