1.

P(-3, 2) is one end of focal chord PQ of the parabola `y^2+4x+4y=0`. Then the slope of the normal at Q is

Answer» Parabola=that tangent at one end of focal chord is parallel to normal at other end.
Slope of normal at `theta`=slope of tangent at P
`y^2+4x+4y=0`
diff with respect to x
`2ydy/dx+4+4dy/dx=0`
`dy/dx=-4/(2y+4)`
`=-1/2`.


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