P_(4)O_(6) reacts with water according to equation, P_(4)O_(6)+6H_(2)Oto4H_(3)PO_(3). Calculate the volume of 0.1 M NaOH solution required to neutralise the acid formed by dissolving 1.1 g of P_(4)O_(6)" in "H_(2)O.

P_(4)O_(6) reacts with water according to equation, P_(4)O_(6)+6H_(2)O

1.	P_(4)O_(6) reacts with water according to equation, P_(4)O_(6)+6H_(2)Oto4H_(3)PO_(3). Calculate the volume of 0.1 M NaOH solution required to neutralise the acid formed by dissolving 1.1 g of P_(4)O_(6)" in "H_(2)O.
Answer» SOLUTION :`{:(P_(4)O_(6)+6H_(2)Oto4H_(3)PO_(4)"(Hydrolysis reaction)"),(H_(3)PO_(3)+2NaOHtoNa_(2)HPO_(3)+2H_(2)O"]"xx4 "(Neutrolisation reaction)"),(overline(underset(=220g)underset(4xx31+6xx16)(P_(4)O_(6))+underset(=320 g)underset(8xx40)(8NaOH )to 4Na_(2)HPO_(3)+2H_(2)O)"(Overall reaction)"):}` Now 220 g of `P_(4)O_(6)` require NAOH for neutralization =320 g `:.` 1.1 g of `P_(4)O_(6)` will require `NaOH=(320)/(220)xx1.1=1.6g` Now 1000 mL of 0.1 MHCl contain `NaOH=40xx0.1=4g` In other words, 4 g of NaOH are present in 0.1 M NaOH `=(1000)/(4)xx1.6=400mL=0.4L`