InterviewSolution
Saved Bookmarks
| 1. |
P and Q are any two points on the circle `x^2+y^2= 4` such that PQ is a diameter. If `alpha` and `beta` are the lengths of perpendiculars from `P` and `Q` on `x + y = 1` then the maximum value of `alphabeta` isA. `(1)/(2)`B. `(7)/(2)`C. 1D. 2 |
|
Answer» Correct Answer - B Let `P(2 cos theta,2 sin theta), Q(-2 cos theta, -2 sin theta)` `:. alpha beta =(|2cos theta+2 sin theta-1||-2cos theta-2 sin theta-1|)/(2)` `=(|4(cos theta+sin theta)^(2)-1|)/(2)` `=(|3+4sin2 theta|)/(2)` `le (7)/(2)` |
|