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P is a variable point on the line L=0 . Tangents are drawn to the circles x^(2)+y^(2)=4 from P to touch it at Q and R. The parallelogram PQSR is completed.If P-= (6,8), then the area of Delta QRS is |
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Answer» `(3sqrt(6))/(25)` sq. units Thereforem the equation of QR (chord of contact ) is `6x+8y=4` or `3x+4y-2=0 ` `:. PM =(48)/(50` and `PQ =SQRT(96)` `QM =sqrt(96-(48^(2))/(25))=sqrt((96)/(25))` `:. QR = 2 sqrt((96)/(25))` `:. ` Area of `Delta PQR =(1)/(2) XX PM xx QR =(192 sqrt(6))/(25)` PQRS is a rhombus. Therefore, Area of `DeltaRS =` Area of `Delta PQR = (192sqrt(6))/(25)` |
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