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P Is An Integer. P Is Greater Than 883.if P -7 Is A Multiple Of 11, Then The Largest Number That Will Always Divide (p+4)(p+15) Is? |
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Answer» p-7= 11*a (as it is MULTIPLE of 11) p=11*(a+7) so (p+4)(p+15)= (11a+7+4)(11a+7+15); = (11a+11)(11a+22); =11*11(a+1)(a+2); =121*2 =242. p-7= 11*a (as it is multiple of 11) p=11*(a+7) so (p+4)(p+15)= (11a+7+4)(11a+7+15); = (11a+11)(11a+22); =11*11(a+1)(a+2); =121*2 =242. |
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