A Hollow Iron Pipe Is 21 Cm Long And Its External Diameter Is 8 Cm. I

1.	A Hollow Iron Pipe Is 21 Cm Long And Its External Diameter Is 8 Cm. If The Thickness Of The Pipe Is 1 Cm And Iron Weighs 8 G/cm3, Then The Weight Of The Pipe Is?
Answer» Given the external diameter = 8 cm. Therefore, the radius = 4 cm. The thickness = 1 cm. Therefore the internal radius = 4 – 1 = 3 cm The volume of the iron = PI (R^2 – r^2)length = 22/7 [(4^2) – (3^2)] 21 = 462 cm3>. Therefore, the weight of iron = 462 * 8 GM = 3.696 kg. Given the external diameter = 8 cm. Therefore, the radius = 4 cm. The thickness = 1 cm. Therefore the internal radius = 4 – 1 = 3 cm The volume of the iron = pi (R^2 – r^2)length = 22/7 [(4^2) – (3^2)] 21 = 462 cm3>. Therefore, the weight of iron = 462 * 8 gm = 3.696 kg.

A Hollow Iron Pipe Is 21 Cm Long And Its External Diameter Is 8 Cm. If The Thickness Of The Pipe Is 1 Cm And Iron Weighs 8 G/cm3, Then The Weight Of The Pipe Is?

Answer»

Given the external diameter = 8 cm. Therefore, the radius = 4 cm.

The thickness = 1 cm. Therefore the internal radius = 4 – 1 = 3 cm

The volume of the iron = PI *(R^2 – r^2)*length = 22/7 *[(4^2) – (3^2)] *21 = 462 cm3>.

Therefore, the weight of iron = 462 * 8 GM = 3.696 kg.

Given the external diameter = 8 cm. Therefore, the radius = 4 cm.

The thickness = 1 cm. Therefore the internal radius = 4 – 1 = 3 cm

The volume of the iron = pi *(R^2 – r^2)*length = 22/7 *[(4^2) – (3^2)] *21 = 462 cm3>.

Therefore, the weight of iron = 462 * 8 gm = 3.696 kg.

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