1.

P-V diagram of an ideal gas is as shown in figure. Work done by the gas in the process ABCD is

Answer»

`4P_(0)V_(0)`
`2P_(0)V_(0)`
`3P_(0)V_(0)`
`P_(0)V_(0)`

SOLUTION :W = area under P-V CURVE
`W_(AB) = -P_(0)V_(0), W_(BC) = 0, W_(CD) = 4P_(0)V_(0)`
`W_(ABCD) = W_(AB) + W_(BC) + W_(CD) = -P_(0)V_(0) + 0 + 4P_(0)V_(0) = 3P_(0)V_(0)`


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