→p=w^i+x^j and →q=y^i+z^j are two vectors in the first quadrant such that |→p|=2|→q|=2r,r>0 and →p⋅→q=0. If →a=w^i+2y^j and →b=x2^i+z^j, then

→p=w^i+x^j and →q=y^i+z^j are two vectors in the first quadrant su

1.	→p=w^i+x^j and →q=y^i+z^j are two vectors in the first quadrant such that \|→p\|=2\|→q\|=2r,r>0 and →p⋅→q=0. If →a=w^i+2y^j and →b=x2^i+z^j, then
Answer» $\to p = w^i + x^j$ and $\to q = y^i + z^j$ are two vectors in the first quadrant such that $\| \to p \| = 2 \| \to q \| = 2 r, r > 0$ and $\to p \cdot \to q = 0$ . If $\to a = w^i + 2 y^j$ and $\to b = \frac{x}{2}^i + z^j$ , then

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→p=w^i+x^j and →q=y^i+z^j are two vectors in the first quadrant such that |→p|=2|→q|=2r,r&gt;0 and →p⋅→q=0. If →a=w^i+2y^j and →b=x2^i+z^j, then

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→p=w^i+x^j and →q=y^i+z^j are two vectors in the first quadrant such that |→p|=2|→q|=2r,r>0 and →p⋅→q=0. If →a=w^i+2y^j and →b=x2^i+z^j, then