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| 1. |
P4+NO3 -1--->PO4*-3 +NO2Balance the rxn by half rxn method |
| Answer» solve equation by oxidation number method : p4 + no3^-1 gives po4^-3 + no2oxidation no of p4 is 0, no3^-1 is 5, po4^-3 is 5 & no2 is 4oxidation: p4 gives 4po4^-3 increases by 20 × 1reduction :no3^-1 gives no2 decreases by 1 × 20p4 gives 4po4^-3 20no3^-1 gives 20no2p4 + 16h2o gives 4po4^-3 20no3^-1 gives 20no2 + 20h2obalanced equation is p4 + 20no3^-1 + 8h+ gives 4po4^-3 + 20no2 + 4h2o | |