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InterviewSolution
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P9 0.18 3b) Calculate the number of moleculesof oxygen gas that occupies a volumeof 224 ml at 273 K and 3 atm pressure. |
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Answer» tion:22400 ml. of oxygen at 273 K temperature and 3-atm pressure = 22400 ×3/1= 67200 ml at STP.So 224 ml of oxygen at 273 K and 3-atm = 224 ×3= 672 ml at STPThe number of Oxygen molecules present in 22400 ml of gas at STP=N(where N= Avagadro Number)Therefore 224 ml of oxygen at 273K and 3-atm pressure will contain =N×672/22400 × N molecules.=3/100×6.022×10 23 =18.066×10 21 Molecules =1.8066×10 22 molecules |
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