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PAGE NoFnd thevalue of Kfor ohiehor to |
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Answer» for identity, L.H.S should be 0 => (cosx+sinx)² +ksinxcosx -1 = 0=> cos²x+sin2x+2sinxcosx+ksinxcosx -1 = 0=> 1+(2+k)sinxcosx -1 = 0=> (2+k)sinxcosx = 0 so, k+2 = 0=> k = -2 |
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