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Parisanstha ki talika |
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Answer» Given a 2
=13 and a 5
=25 We know that a
=a+(n−1)d ∴a 2
=a+(2−1)d ⇒13=a+(2−1)d ⇒a+d=13 ...(i) and a 5
=a+(5−1)d ⇒25=a+4d ⇒a+4d=25 ...(ii) Now, subtracting (i) from (ii), we get 3d=12 ⇒d=4 Now a+d=13 [from (i)] ⇒a=9 Hence, a 7
=a+6d=9+6(4) ⇒a 7
=33 |
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