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Partial derivative of x4 – x2y2 + y4 w.r.t. y at point (-1,1). a) -2 b) 2 c) -1 d) 1

Answer»

Let f(x , y) = x4 - x2y2 + y4

\(\frac{\partial f}{\partial y}\) = -2x2 + 4y3

\(\frac{\partial f}{\partial y}(-1, 1)\) = -2(-1)2 x 1 + 4 x 13

 = -2 + 4 = 2



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