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Partial pressure of (p) is in proportional to the concentration (c) - explain. |
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Answer» Solution :For REACTIONS involving gases, however, it is usually more convenient to express the equilibrium CONSTANT in terms of partial PRESSURE. Equation of idea gas pV nRT ....(Eq.-i) `therefore p=(n/V)RT` …..(Eq. ii) If concentration =c mol `L^(-1)` OR mol/`dm^3` `therefore` p=cRT=[gas]RT ...(Eq. iii) where , R=0.0831 bar L `mol^(-1) K^(-1)` where, p = Pressure in pascal, n = Number of mol of the gas, V = Volume of gas `m^3` T = Temperature in Kelvin, `therefore n/V`= Concentration expressed in mol/`m^3` `therefore` At constant temperature, the p of the gas is proportional to its concentration p`prop`[gas], `1_"Pascal"=1 Nm^(-2)` and 1 bar = `10^5` Pa 1.013 bar =1 atm . |
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