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Particles of masses 10 g and 20 g have position vectors (5,3,0) and (2,0,3) respectively. The position vector of their centre of mass is ………… cm. |
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Answer» `(1,2,3)` `m_(2)=20g,vec(r_(2))=[2,0,3]cm` `therefore vec(r)_(cm)=(m_(1)vec(r_(1))+m_(2)vec(r_(2)))/(m_(1)+m_(2))=(10(5,3,0)+20(2,0,3))/(10+20)` `therefore vec(r)_(cm)=((50,30,0)+(40,0,60))/(30)=(("90, 30, 60"))/(30)` `therefore vec(r)_(cm)=(3,1,2)cm` |
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