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Particles of masses 3 kg, 4 kg, 5 kg nd 2 kg are placed at points `A(3,2), B(-2,2), C(-2,-3)` and `D(1,-2)` respectively of a co-ordinate system. The centre of mass of the system is atA. `(-(1)/(2),-(1)/(2))`B. `(-(1)/(2),-(5)/(14))`C. `(0,-(1)/(2))`D. (0,0) |
Answer» Correct Answer - B (i) `x = (m_(1)n_(1)+m_(2)x_(2)+m_(2)x_(3)+m_(4)x_(4))/(m_(1)+m_(2)+m_(3)+m_(4))=(-7)/(14)=(-1)/(2)` (ii) `y=(m_(1)y_(1)+m_(2)y_(2)+m_(3)y_(3)+m_(4)y_(4))/(m_(1)+m_(2)+m_(3)+m_(4))=(-5)/(14)` (x,y) of centre of mass `=((-1)/(2), (-5)/(14))`. |
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