1.

PASSAGE-I: An elevator weighing 500 kg is to be lifted up at a constant velocity of 0.4 m s-1. For this purpose a motor of required horse power is used.​

Answer»

Answer:

POWER = WORK DONE / TIME

= mgd/t

= 1500×10×0.4/1

= 2000W

HOPE ITS HELPFUL



Discussion

No Comment Found

Related InterviewSolutions