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Passage: Whenall the coefficients ina balancedchemical equationare multipliedbya constant factor X the equilibrium constant (originallyK) becomes K^J.Similarly,whenbalancedequations are addedtogether, the equilibrium constant for the combined process is equal to the product of the equilibrium constants for eachstep.Equilibrium constant of the reversedreactionis numericallyequal tothe reciprocal of the equilibrium constant of the original equation. Unit of K_p = ("atm")^(Deltan) , Unit of K_c =("mol" L^(-1))^(Deltan) The equilibrium constants for the following reactions at 1400 K are given: 2H_2O_((g)) harr 2H_(2(g))+O_(2(g)) , K_1=2.1 xx 10^(-13) 2CO_(2(g)) harr 2CO_((g))+O_(2(g)) , K_2=1.4 xx 10^(-12) Then the equilibrium constant K for the reaction, H_(2(g))+CO_(2(g)) harr CO_((g)) + H_2O_((g)) is |
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Answer» 2.04 |
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