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Path of a particle moving in `x-y` plane is `y=3x+4`. At some instant suppose `x`- component of velocity is `1m//s` and it is increasing at a constant rate of `1m//s^(2)`. Then at this instant.A. speed of particle is `sqrt(10)m//s`B. acceleration of particle is `sqrt(10)m//s`C. velocity time graph is parabolaD. acceleration time graph is parabola |
Answer» Correct Answer - A::B |
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