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Pawan can build a wall in x days and kasim can do the same build in 4x days. Quantity I: If both of them together complete half of the wall in 20 days then what is the value of x?Quantity II: If Pawan can build half of the wall at 25% of his efficiency in 35 days then what is the value of x? 1. Quantity 1 > Quantity 22. Quantity 1 ≥ Quantity 23. Quantity 1 < Quantity 24. Quantity 1 ≤ Quantity 25. Quantity 1 = Quantity 2 |
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Answer» Correct Answer - Option 1 : Quantity 1 > Quantity 2 Given: Pawan = x days Kasim = 4x days Formula used: Work done in t1 and t2 days then, total work done = (1/t1) + (1/t2) Calculation: Quantity I: half of the work in 20 days therefore, the complete work in 20 × 2 = 40 days ⇒ (1/x) + (1/4x) = (1/40) ⇒ 5 × 40 = 4x ⇒ x = 50 Quantity II: Let P’s efficiency = a ⇒ then 25% of a = 0.25a ⇒ half of the work in 35 days then the complete work in 35 × 2 = 70 days ⇒ 0.25a efficiency he does work in 70 days ⇒ Total work = 70 × 0.25a ⇒ Total work = 17.5a units ⇒ at ‘a’ efficiency he will do work in 17.5a/a = 17.5 days ∴ Quantity I > Quantity II |
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