1.

`PbCl_(2)` is insoluble in cold water. Addition of HCl increases its solubility due toA. formation of soluble complex anions like ``B. oxidation of Pb(II) to Pb(IV)C. formation of ``D. formation of polymeric lead complexes .

Answer» Correct Answer - A
Addition of `Cl^(-)` ions to a of suspension `PbCl_2` gives rise to soluble complex ions :
`PbCl_2`(s) + `Cl^(-)`(aq) `` `[PbCl_3]^(-)`(aq)
`PbCl_2`(s) + `2Cl^(-)`(aq) `` `[PbCl_4]^(2-)`(aq) .


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