`PbCl_(2)` is insoluble in cold water. Addition of HCl increases its solubility due toA. formation of soluble complex anions like `[PbCl_(3)]^(-)`B. oxidation of `Pb(II)` to `Pb(IV)`C. formation of `[Pb(H_(2)O)_(6)]^(2+)`D. formation of polymeric lead complexes

`PbCl_(2)` is insoluble in cold water. Addition of HCl increases its s

1.	`PbCl_(2)` is insoluble in cold water. Addition of HCl increases its solubility due toA. formation of soluble complex anions like `[PbCl_(3)]^(-)`B. oxidation of `Pb(II)` to `Pb(IV)`C. formation of `[Pb(H_(2)O)_(6)]^(2+)`D. formation of polymeric lead complexes
Answer» Correct Answer - A Addition of `Cl^(-)` ion to a suspension of `PbCl_(2)` leads to the formation of soluble complex as shown below : `underset(PbCl_(2))(PbCl_(2)) + Cl^(-) rarr underset(" Soluble complex ")([PbCl_(3)]^(-))`.

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