PbO andPBO_(2) react with hci according tofollowing chemical equation 2 Pbo +HCI rarr 2 PbCI_(2)+2H_(2)O PBO_(2)+4 HCI rarr PbCI_(2)+CI_(2)+2H_(2)O why do these compounds differ in their reactivity ?

PbO andPBO_(2) react with hci according tofollowing chemical equation

1.	PbO andPBO_(2) react with hci according tofollowing chemical equation 2 Pbo +HCI rarr 2 PbCI_(2)+2H_(2)O PBO_(2)+4 HCI rarr PbCI_(2)+CI_(2)+2H_(2)O why do these compounds differ in their reactivity ?
Answer» Solution :Writing the O.N of each element above its symbol in the following reaction s we have in raction (i) O.N of none of the atoms undergo change THEREFORE it is not a ardox reeaction it is fact an acid base reaction since `PbO_(2)` being a basic with HCIto form `PbCI_(2)` and `H_(2)O` `PbO+2HCIrarrPbCI_(2)+H_(2)O` in reaction (ii) Pb in `PbO_(2)` is present in +4 oxidation state since DUE to inert pari EFFECT +2 oxide state of Pb is moire stable therefore `PbO_(2)` ACTS as an oxidisning agent as RESUTL it oxidises `CDI^(-) to CI_(2)` itself gets reduced to `Pb^(2+)` in tother words reaction of `PbO_(2)` with HCI is a redox reaction `PbO_(2) +4 HCI rarrPbCI_(2) +CI_(2)+2H_(2)O` Thus the two compuntds differ in their reactivity beacuse they undergo different types of reactions