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PbOandPbO_(2) react with HCl according to following chemical equations (i) 2PbO+4HCl to2PbCl_(2)+2H_(2)O (ii) PbO_(2)+4HCl toPbCl_(2)+Cl_(2)+2H_(2)O Why do these compounds differ in their reactivity ? |
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Answer» SOLUTION :(i) `overset(+2)(2Pb)overset(-2)(O)+overset(+1)(4H)overset(-1)(CL) tooverset(+2)(2Pb)overset(-1)(Cl_(2))+overset(+1)(2H_(2))overset(-2)(O)` OXIDATION number of element does not change so this REACTION is not redox reaction. It is acid- base reaction. (ii) In given reaction `Pb^(+4)` is convert into `Pb^(+2)`, so `PbO_(2)` is oxidising agent and `Cl^(-)` is oxidise in `Cl_(2)`. |
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