1.

PCI_5dissociates to 25% in a three litre flask. To what volume the container must be changed such that PCI_5 dissociates to 50% extent

Answer»

18
12
6
24

Solution :
`K_(C)=((calpha)(calpha))/(C(1-alpha))=(Calpha^(2))/(1-alpha)=(nalpha^(2))/(V(1-alpha))`
`K_(C)` is constant
`:. (alpha^(2))/(V_(1)(1-alpha))=(f^(2))/(V_(2)(1-beta))`
`((0.25)^(2))/(3(1-0.25))=((0.5)^(2))/(V_(2)(1-0.5)), V_(2)=18`


Discussion

No Comment Found