PCl_(3),Cl_(2),PCl_(5) are in equilibrium in a closed vessel at 500K. The equilibrium concentration are 1.6 mol L^(-1), 1.6"mol" L^(-1)and1.4"mol"L^(-1) respectively. Calculate K_(c)andK_(p)" for "PCl_(5)(g)hArrPCl_(3)(g)+Cl_(2)(g).

PCl_(3),Cl_(2),PCl_(5) are in equilibrium in a closed vessel at 500K.

1.	PCl_(3),Cl_(2),PCl_(5) are in equilibrium in a closed vessel at 500K. The equilibrium concentration are 1.6 mol L^(-1), 1.6"mol" L^(-1)and1.4"mol"L^(-1) respectively. Calculate K_(c)andK_(p)" for "PCl_(5)(g)hArrPCl_(3)(g)+Cl_(2)(g).
Answer» Solution :`K_(C)=([PCl_(3)][Cl_(2)])/([PCl_(5)])=(1.6xx1.6)/1.4=1.828` `DELTAN=2-1=1` `thereforeK_(p)=K_(c)(RT)^(Deltan)" BECOMES "=1.828(0.0831xx500)^(1)=75.95`.