1.

Pcl5 =pcl3+cl2 when .03 mole of pcl5 was brought to equilibrium at 500k the equilibrium volume was 2.05l the value of kp

Answer»

Explanation:

PCL5 =pcl3+cl2 when .03 MOLE of pcl5 was BROUGHT to EQUILIBRIUM at 500k the equilibrium volume was 2.05l the value of KP



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