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Peak to peak voltage is given by ________(a) Vp-p = number of units × \((\frac{1}{division})\)(b) Vp-p = \((\frac{volts}{division})\)(c) Vp-p = number of units × volts(d) Vp-p = number of units × \((\frac{volts}{division})\)This question was addressed to me in quiz.My question is from CRO Measurements in division Oscilloscopes of Electrical Measurements |
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Answer» CORRECT OPTION is (d) Vp-p = number of UNITS × \((\frac{volts}{division})\) EASIEST explanation: In a Cathode RAY Oscilloscope, the peak to peak voltage is given by the relation, Vp-p = number of units × \((\frac{volts}{division})\) where, Vp-p is the peak to peak voltage. |
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