Percentage of Se in peroxidase anhydrase enzyme is `0.5%` by weight (at. Wt. `=78.4)`, then minimum molecular weight of peroxidase anhydrase enzyme is:A. (a)`1.568xx10^(3)`B. (b)`15.68`C. (c )`1.568xx10^(4)`D. (d)`2.136xx10^(4)`

Percentage of Se in peroxidase anhydrase enzyme is `0.5%` by weight (a

1.	Percentage of Se in peroxidase anhydrase enzyme is `0.5%` by weight (at. Wt. `=78.4)`, then minimum molecular weight of peroxidase anhydrase enzyme is:A. (a)`1.568xx10^(3)`B. (b)`15.68`C. (c )`1.568xx10^(4)`D. (d)`2.136xx10^(4)`
Answer» Correct Answer - C Suppose the mol. Wt. of enzyme =x Given `100 g` of enzyme wt of `Se=0.5 g` `:.` In x g of enzyme wt. of Se` =0.5/100 xx x` Hence `78.4=(0.5xx x)/100` `:. X=15680=1.568xx10^(4)`

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Percentage of Se in peroxidase anhydrase enzyme is `0.5%` by weight (at. Wt. `=78.4)`, then minimum molecular weight of peroxidase anhydrase enzyme is:A. (a)`1.568xx10^(3)`B. (b)`15.68`C. (c )`1.568xx10^(4)`D. (d)`2.136xx10^(4)`

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